Day 33

Last Stone Weight II

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class Solution {
public int lastStoneWeightII(int[] stones) {
int sum = 0;
for (int num : stones) {
sum += num;
}
int space = sum / 2;
int[] dp = new int[space + 1];

for (int i = 0; i < stones.length; i++) {
for (int j = space; j >= stones[i]; j--) {
dp[j] = Math.max(dp[j], dp[j - stones[i]] + stones[i]);
}
}
return sum - 2 * dp[space];
}
}
go
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func lastStoneWeightII(stones []int) int {
sum := 0
for _, stone := range stones {
sum += stone
}

space := sum / 2
dp := make([]int, space+1)

for _, stone := range stones {
for j := space; j >= stone; j-- {
dp[j] = max(dp[j], dp[j-stone]+stone)
}
}

return sum - 2*dp[space]
}

Target Sum

left + right = sum; left - right = target; left = (sum + target) / 2

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class Solution {
public int findTargetSumWays(int[] nums, int target) {
int sum = 0;
for (int num : nums) {
sum += num;
}
if (Math.abs(target) > sum) {
return 0;
}
if ((sum + target) % 2 == 1) {
return 0;
}
int space = (sum + target) / 2;
int[] dp = new int[space + 1];

dp[0] = 1;
for (int i = 0; i < nums.length; i++) {
for (int j = space; j >= nums[i]; j--) {
dp[j] += dp[j - nums[i]];
}
}

return dp[space];
}
}
go
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func findTargetSumWays(nums []int, target int) int {
sum := 0
for _, num := range nums {
sum += num
}

if abs(target) > sum {
return 0
}
if (target+sum)%2 == 1 {
return 0
}

space := (target + sum) / 2
dp := make([]int, space+1)
dp[0] = 1
for _, num := range nums {
for j := space; j >= num; j-- {
dp[j] += dp[j-num]
}
}
return dp[space]
}

func abs(x int) int {
return int(math.Abs(float64(x)))
}

Ones and Zeroes

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class Solution {
public int findMaxForm(String[] strs, int m, int n) {
int[][] dp = new int[m + 1][n + 1];
for (String str : strs) {
int oneNum = 0, zeroNum = 0;
for (char c : str.toCharArray()) {
if (c == '0') {
zeroNum++;
} else {
oneNum++;
}
}
for (int i = m; i >= zeroNum; i--) {
for (int j = n; j >= oneNum; j--) {
dp[i][j] = Math.max(dp[i][j], dp[i - zeroNum][j - oneNum] + 1);
}
}
}
return dp[m][n];
}
}
go
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func findMaxForm(strs []string, m int, n int) int {
dp := make([][]int, m+1)
for i, _ := range dp {
dp[i] = make([]int, n+1)
}

for i := 0; i < len(strs); i++ {
zeroNum, oneNum := 0, 0
for _, v := range strs[i] {
if v == '0' {
zeroNum++
} else {
oneNum++
}
}

for j := m; j >= zeroNum; j-- {
for k := n; k >= oneNum; k-- {
dp[j][k] = max(dp[j][k], dp[j-zeroNum][k-oneNum]+1)
}
}
}
return dp[m][n]
}