Day 39

Longest Increasing Subsequence

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class Solution {
public int lengthOfLIS(int[] nums) {
int[] dp = new int[nums.length];
Arrays.fill(dp, 1);
int res = 1;
for (int i = 0; i < nums.length; i++) {
for (int j = 0; j < i; j++) {
if (nums[i] > nums[j]) {
dp[i] = Math.max(dp[i], dp[j] + 1);
}
}
res = Math.max(res, dp[i]);
}
return res;
}
}
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func lengthOfLIS(nums []int) int {
dp := make([]int, len(nums))
res := 1
for i := 0; i < len(nums); i++ {
dp[i] = 1
}

for i := 1; i < len(nums); i++ {
for j := 0; j < i; j++ {
if nums[i] > nums[j] {
dp[i] = max(dp[i], dp[j]+1)
}
}
res = max(res, dp[i])
}
return res
}
func max(x, y int) int {
if x > y {
return x
}
return y
}

Longest Continuous Increasing Subsequence

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class Solution {
public int findLengthOfLCIS(int[] nums) {
int[] dp = new int[nums.length];
Arrays.fill(dp, 1);
int res = 1;
for (int i = 1; i < nums.length; i++) {
if (nums[i] > nums[i - 1]) {
dp[i] = Math.max(dp[i], dp[i - 1] + 1);
res = Math.max(res, dp[i]);
}
}
return res;
}
}
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func findLengthOfLCIS(nums []int) int {
dp, res := make([]int, len(nums)), 1
for i := range dp {
dp[i] = 1
}
for i := 1; i < len(nums); i++ {
if nums[i] > nums[i-1] {
dp[i] = max(dp[i], dp[i-1]+1)
}
res = max(res, dp[i])
}
return res
}

func max(a, b int) int {
if a > b {
return a
}
return b
}

Maximum Length of Repeated Subarray

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class Solution {
public int findLength(int[] nums1, int[] nums2) {
int[][] dp = new int[nums1.length + 1][nums2.length + 1];
int res = 0;
for (int i = 1; i < nums1.length + 1; i++) {
for (int j = 1; j < nums2.length + 1; j++) {
if (nums1[i - 1] == nums2[j - 1]) {
dp[i][j] = dp[i - 1][j - 1] + 1;
res = Math.max(res, dp[i][j]);
}
}
}
return res;
}
}
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func findLength(A []int, B []int) int {
m, n := len(A), len(B)
res := 0
dp := make([][]int, m+1)
for i := 0; i <= m; i++ {
dp[i] = make([]int, n+1)
}

for i := 1; i <= m; i++ {
for j := 1; j <= n; j++ {
if A[i-1] == B[j-1] {
dp[i][j] = dp[i-1][j-1] + 1
}
if dp[i][j] > res {
res = dp[i][j]
}
}
}
return res
}