Day 41

Is Subsequence

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// Two pointers
class Solution {
    public boolean isSubsequence(String s, String t) {
        if (s.length() == 0) return true;
        int p1 = 0;
        for (char tc : t.toCharArray()) {
            if (s.charAt(p1) == tc) {
                p1++;
                if (p1 == s.length()) return true;
            }
        }
        return p1 == s.length();
    }
}
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/// dp
class Solution {
    public boolean isSubsequence(String s, String t) {
        int[][] dp = new int[s.length() + 1][t.length() + 1];
        for (int i = 1; i <= s.length(); i++) {
            char sc = s.charAt(i - 1);
            for (int j = 1; j <= t.length(); j++) {
                char tc = t.charAt(j - 1);
                if (sc == tc) {
                    dp[i][j] = dp[i - 1][j - 1] + 1;
                } else {
                    dp[i][j] = dp[i][j - 1];
                }
            }
        }
        return dp[s.length()][t.length()] == s.length();
    }
}
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func isSubsequence(s string, t string) bool {
	dp := make([][]int, len(s)+1)
	for i := range dp {
		dp[i] = make([]int, len(t)+1)
	}
	for i := 1; i <= len(s); i++ {
		for j := 1; j <= len(t); j++ {
			if s[i-1] == t[j-1] {
				dp[i][j] = dp[i-1][j-1] + 1
			} else {
				dp[i][j] = dp[i][j-1]
			}
		}
	}
	return dp[len(s)][len(t)] == len(s)
}

Distinct Subsequences

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class Solution {
    public int numDistinct(String s, String t) {
        int[][] dp = new int[s.length() + 1][t.length() + 1];
        for (int i = 0; i < s.length() + 1; i++) {
            dp[i][0] = 1;
        }
        for (int i = 1; i <= s.length(); i++) {
            for (int j = 1; j <= t.length(); j++) {
                if (s.charAt(i - 1) == t.charAt(j - 1)) {
                    // s: bagg, t:bag
                    dp[i][j] = dp[i - 1][j - 1] + dp[i - 1][j];
                } else {
                    dp[i][j] = dp[i - 1][j];
                }
            }
        }
        return dp[s.length()][t.length()];
    }
}
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func numDistinct(s string, t string) int {
	dp := make([][]int, len(s)+1)
	for i := 0; i < len(dp); i++ {
		dp[i] = make([]int, len(t)+1)
	}
	for i := 0; i < len(dp); i++ {
		dp[i][0] = 1
	}
	for i := 1; i <= len(s); i++ {
		for j := 1; j <= len(t); j++ {
			if s[i-1] == t[j-1] {
				dp[i][j] = dp[i-1][j-1] + dp[i-1][j]
			} else {
				dp[i][j] = dp[i-1][j]
			}
		}
	}
	return dp[len(s)][len(t)]
}

Delete Operation for Two Strings

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class Solution {
    public int minDistance(String word1, String word2) {        int len1 = word1.length();
        int[][] dp = new int[word1.length() + 1][word2.length() + 1];
        for (int i = 1; i <= word1.length(); i++) {
            dp[i][0] = i;
        }
        for (int j = 1; j <= word2.length(); j++) {
            dp[0][j] = j;
        }
        for (int i = 1; i <= word1.length(); i++) {
            for (int j = 1; j <= word2.length(); j++) {
                if (word1.charAt(i - 1) == word2.charAt(j - 1)) {
                    dp[i][j] = dp[i - 1][j - 1];
                } else {
                    dp[i][j] = Math.min(Math.min(dp[i - 1][j - 1] + 2, dp[i - 1][j] + 1), dp[i][j - 1] + 1);
                }
            }
        }
        return dp[word1.length()][word2.length()];
    }
}
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func minDistance(word1 string, word2 string) int {
	dp := make([][]int, len(word1)+1)
	for i := 0; i < len(dp); i++ {
		dp[i] = make([]int, len(word2)+1)
	}
	for i := 0; i < len(dp); i++ {
		dp[i][0] = i
	}
	for j := 0; j < len(dp[0]); j++ {
		dp[0][j] = j
	}
	for i := 1; i < len(dp); i++ {
		for j := 1; j < len(dp[i]); j++ {
			if word1[i-1] == word2[j-1] {
				dp[i][j] = dp[i-1][j-1]
			} else {
				dp[i][j] = min(min(dp[i-1][j]+1, dp[i][j-1]+1), dp[i-1][j-1]+2)
			}
		}
	}
	return dp[len(dp)-1][len(dp[0])-1]
}

func min(a, b int) int {
	if a < b {
		return a
	}
	return b
}